# Line slope calculator 5x-8y=-30

**Straight line given by points A[2; 5] and B[10; 10]**

## Calculation:

**Slope-intercept form of line:**y = 0.625x+3.75

**Canonical form of the line equation:**5x-8y+30 = 0

**Parametric form of the line equation:**

x = 8t+2

y = 5t+5 ; t ∈ R

**Slope:**m = 0.625

**Slope angle of line: φ =**32°19″ = 0.5586 rad

**X intercept:**x

_{0}= -6

**Y intercept:**y

_{0}= q = 3.75

**Distance line from the origin:**d

_{0}= 3.18

**The length of the segment AB: |AB| =**9.434

**Vector: AB =**(8; 5)

**Normal vector: n =**(5; -8)

**Midpoint of the segment AB: M =**[6; 7.5]

**Perpendicular Bisector equation:**8x+5y-85.5 = 0

**Vector OA = (2; 5) ; |OA| = 5.3852**

**Vector OB = (10; 10) ; |OB| = 14.1421**

**Scalar product OA .OB = 70**

**Angle ∠ AOB = 23°11'55″ = 0.4049 rad**