# Line slope calculator 5x-4y=1

**Straight line given by points A[1; 1] and B[5; 6]**

## Calculation:

**Slope-intercept form of line:**y = 1.25x-0.25

**Canonical form of the line equation:**5x-4y-1 = 0

**Parametric form of the line equation:**

x = 4t+1

y = 5t+1 ; t ∈ R

**Slope:**m = 1.25

**Slope angle of line: φ =**51°20'25″ = 0.8961 rad

**X intercept:**x

_{0}= 0.2

**Y intercept:**y

_{0}= q = -0.25

**Distance line from the origin:**d

_{0}= 0.1562

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(4; 5)

**Normal vector: n =**(5; -4)

**Midpoint of the segment AB: M =**[3; 3.5]

**Perpendicular Bisector equation:**4x+5y-29.5 = 0

**Vector OA = (1; 1) ; |OA| = 1.4142**

**Vector OB = (5; 6) ; |OB| = 7.8102**

**Scalar product OA .OB = 11**

**Angle ∠ AOB = 5°11'40″ = 0.0907 rad**